next up previous
Next: 3.4 Continuum Discretized Coupled Up: 3 Basic theory and Previous: 3.3.0.1 Example 4: DWBA

Example 4: DWBA


DWBA 14N(7Be,8B)13C
NAMELIST
 &FRESCO hcm=0.100 rmatch=60.000 rintp=0.20 
	 hnl=0.100 rnl=12.00 centre=0.25 rsp=0.0 jtmin=0.0 
	 jtmax=150.0 absend=-0.0010 dry=F 
	 thmin=0.00 thmax=60.00 thinc=0.5
	 ips=0.0000 iter=1 pralpha=F nnu=24 chans=1 smats=2  
	 xstabl=1 pel=1 exl=1 lab=1 lin=1 lex=1 elab=84.0000 
	 fatal=T nosol=F psiren=F  /


 &PARTITION namep='Be7' massp=7.0169 zp=4 namet='14N' 
	 masst=14.0033 zt=7 qval=0.0000 pwf=T nex=1  /
 &STATES jp=0.0 bandp=1 ep=0.0000 cpot=1 jt=0.0 
	 bandt=1 et=0.0000 fexch=F  /

 &PARTITION namep='B8' massp=8.0246 zp=5 namet='C13' 
	 masst=13.0033 zt=6 qval=-7.414 pwf=T nex=1  /
 &STATES jp=1.5 bandp=-1 ep=0.0000 cpot=2 jt=0.5 
	 bandt=-1 et=0.0000 fexch=F  /

 &partition /
 
 &POT kp=1 itt=F ap=7.000 at=14.000 rc=0.697  /
 &POT kp=1 type=1 itt=F 
	p1=79.1 p2=0.763 p3=0.88 
	p4=36.0 p5=0.837 p6=0.98  /

 &POT kp=2 itt=F ap=1.000 at=0.000 rc=2.939  /
 &POT kp=2 type=1 itt=F 
	p1=85.200 p2=3.300 p3=0.910 
	p4=39.300 p5=3.760 p6=1.020 /

 &POT kp=3 itt=F ap=0.0 at=13. rc=1.3  /	
 &POT kp=3 type=1 itt=F p1=54. p2=1.3 p3=0.650  /
 &POT kp=4 itt=F ap=1.000 at=0.000 rc=2.391  /
 &POT kp=4 type=1 itt=F 
	p1=44.675 p2=2.391 p3=0.520  /
 &POT kp=4 type=3 itt=F p1=4.898 p2=2.391 p3=0.520  /
 &POT kp=5 itt=F ap=7.0 at=13. rc=1.  /
 &POT kp=5 type=1 itt=F p1=54.3 p2=0.92 p3=0.79 
	 p4=29.9 p5=1.03 p6=0.69 p7=0.000  /
 &pot / 
 
 &OVERLAP kn1=10 ic1=1 ic2=2 in=2 nn=1 l=1 sn=0.5 
	 j=0.5 kbpot=3 be=7.5506 isc=1 ampl=0.0000  /
 &OVERLAP kn1=1 ic1=2 ic2=1 in=1 nn=1 l=1 sn=0.5 
	 j=1.5 kbpot=4 be=0.1370 isc=1  /
 &overlap / 
 
 &COUPLING icto=2 icfrom=1 kind=7 ip1=1 ip2=-1 ip3=5  /
 &CFP in=2 ib=1 ia=1 kn=10 a=0.87  /
 &CFP in=1 ib=1 ia=1 kn=1 a=1  /
 &cfp / 
 
 &coupling / 

 



Antonio Moro 2004-10-27